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Question

If in the expansion of (1+x)m (1x)n the coefficients of x and x2 are 3 and –6 respectively, then m is

A
6
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B
9
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C
12
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D
24
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Solution

The correct option is C 12
(1+x)m (1x)n=(1+mx+m(m1)2x2+...)×(1nx+n(n1)2x2+...)Coefficient of x=mn=3 (given)Coefficient of x2=n(n1)2nm+m(m1)2=6 (given) n2n2mn+m2m=12(mn)2(m+n)=12 (3)2(m+n)=12m+n=21 Solving mn=3, m+n=21, we get m=12, n=9

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