If in the expansion of (a+b)n and (a+b)n+3, the ratio of the coefficients of second and third terms, and third and fourth terms respectively are equal, then n is
5
n =5
Coefficients of the 2nd and 3rd terms in (a+b)n are nC1 and nC2
Coefficients of the 3rd and 4th terms in (a+b)n+3 are n+3C2 and n+3C3
Thus, we have
nC1nC2=n+3C2n+3C3
⇒2n−1=3n+1
⇒2n+2=3n−3
⇒n=5