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Question

If in the expansion of x4-1x315, x-17 occurs in rth term, then
(a) r = 10
(b) r = 11
(c) r = 12
(d) r = 13

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Solution

(c) r = 12

Here,
Tr=Cr-115 (x4)15-r+1 -1x3r-1=(-1)r× Cr-115 x64-4r-3r+3For this term to contain x-17, we must have:67-7r=-17r=12

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