Question

If in the given parallelogram AE = CF = 16 cm and BD = 28 cm, then what is its area?

• A. $448{\text{cm}}^2$
• B. $348{\text{cm}}^2$
• C. $224{\text{cm}}^2$
• D. $368{\text{cm}}^2$

Answer 1

The correct option is A $448{\text{cm}}^2$

Area of the parallelogram equals the sum of areas of triangles ADB and BDC.
Area of $△ADB=\frac{1}{2}\times DB\times AE=\frac{1}{2}\times 28\times 16=224c{m}^2$

Similarly, since CF = AE we have
area of $△BDC=224c{m}^2$
Thus, $\text{Area of ABCD}=2\times 224c{m}^2=448c{m}^2$