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Question

If in the multiplication of [ab−ba] and [cd−dc], A and B are the elements of the first row, then the elements of the second row will be

A
B,A
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B
A,B
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C
B,A
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D
B,A
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Solution

The correct option is C B,A

A B

Consider, [abba][cddc]=[acbdad+bcbcadbd+ac]

B A
Hence, the elements of the second row are B,A

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