Question

If, in the reaction $N_2{O}_4\left(g\right)\rightleftharpoons 2N{O}_2\left(g\right),$ one mole of $N_2{O}_4$ taken initially and $x$ is that part of $N_2{O}_4$ which dissociates, then the number of moles at equilibrium will be:

• A. $1$
• B. $3$
• C. $(1+x)$
• D. $(1+x{)}^2$

Answer 1

The correct option is C $(1+x)$

The given reaction is $N_2{O}_4\rightleftharpoons 2N{O}_2$
$\begin{array}{ccc}t=0& 1& 0\\ t_{eq}& 1-x& 2x\end{array}$
Total number of moles at equilibrium $=1-x+2x=(1+x)$