Question

If in the reaction $N_2{O}_4\rightleftharpoons 2N{O}_2$, $a$ is that part of $N_2{O}_4$ which dissociates, then the number of moles at equilibrium will be:

• A. $1-a$
• B. $(1+a{)}^2$
• C. $(1-a{)}^2$
• D. $(1+a)$

Answer 1

The correct option is D $(1+a)$

$N_2{O}_4\rightleftharpoons 2N{O}_{2}att=010at{eqb}^{m}1-a2a$

Total no. of moles at equilibrium=$1-a+2a=1+a$