Question

If in the $△ABC$ the equation of the side $BC$ is $x+2y=3,$ the vertex $A$ is $(1,2)$ and the abscissa of the orthocentre is $3,$ then the ordinate of the orthocentre is

• A. $6$
• B. $4$
• C. $2$
• D. $0$

Answer 1

The correct option is A $6$

Here, $BC$ is $x+2y=3,$

Altitude from $A$ is perpendicular to $BC.$

The equation of altitude from A with slope $2$ is $y-2=2(x-1)$
=>$y=2x$
Abscissa is $x=3$, then ordinate is $6.$