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Question

If in ABC, sinAsinC=sin(AB)sin(BC),
Prove that a2,b2,c2 are in A.P.

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Solution

sinA=sin(B+C) or
sin2Bsin2C=sin2Asin2B
or 2b2=a2+c2 by sine rule
a2,b2,c2 are in A.P.

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