If in two triangles ABC and PQR , AB = PQ, AC = QP and BC = QR then
A
∆ ACB ≅ ∆ PQR
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B
∆ ABC ≅ ∆ PRQ
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C
∆ ACB ≅ ∆ PRQ
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D
∆ ABC ≅ ∆ PQR
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Solution
The correct option is D ∆ ABC ≅ ∆ PQR If in two triangles ABC and PQR , AB = PQ, AC = QP and BC = QR then ∆ ABC ≅ ∆ PQR. Since the sides of ∆ ABC is equal to the corresponding sides of ∆ PQR, the two triangles are congruent using SSS postulate.