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Question

If instantaneous current in a circuit is given byl=(3+4sinωt)A os then the maximum value of current in the circuit is

A
4 A
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B
5 A
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C
7 A
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D
3 A
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Solution

The correct option is C 7 A
i=A(3+4sinwt)A
maximum when the term
i=3+4sinwt is maximum.
so it maximum for
wt= π/2
so i=3+4sinπ/2 =32+42=5 Amp
i=7 Ampere

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