If -0bdx-1-x2-b -dx-1-x2-then b-

Tan^ 1b=tan^ 1∞ tan^ 1b 2 nbsp;tan^ 1b= π/2 ⇒ b=1 ...

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Second Fundamental Theorem of Calculus

If ∫0bdx/1+x2...

Question

If $\int_{0}^{b} \frac{d x}{1 + x^{2}} = \int_{b}^{\infty} \frac{d x}{1 + x^{2}}$ ,then b=

$t a n^{- 1} (\frac{1}{3})$

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$\frac{\sqrt{3}}{2}$

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$\sqrt{2}$

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If $\int_{0}^{b} \frac{d x}{1 + x^{2}} = \int_{b}^{\infty} \frac{d x}{1 + x^{2}}$ ,then b=

$I f \frac{d}{d x} [\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}] = a x + b t h e n (a, b) =$

y = a [x + \sqrt{x^{2} + 1}]^{n} + b [x - \sqrt{x^{2} + 1}]^{- n}

(x^{2} - 1) \frac{d^{2} y}{d x^{2}} + x \frac{d y}{d x} - n^{2} y = 0

y = \frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}

\frac{d y}{d x} = a x + b

a

b

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