If -0-2cosx dx - a then -0-cosx dx is equal to -

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Area between x=g(y) and y Axis

If ∫0π/2cosx ...

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If $\int_{0}^{\frac{π}{2}} c o s (x) d x = a t h e n \int_{0}^{π} c o s (x) d x$ is equal to -

2 a

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a^{2}

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0

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a

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\int_{0}^{\frac{π}{2}} c o s (x) d x = a t h e n \int_{0}^{π} c o s (x) d x

\int_{0}^{\frac{π}{2}} cos x d x = a

\int_{0}^{π} cos x d x =

I_{1} = \int_{0}^{π / 2} cos (sin x) d x

I_{2} = \int_{0}^{π / 2} sin (cos x) d x

I_{3} = \int_{0}^{π / 2} cos x d x

\frac{π}{2} \int 0 \frac{2^{sin x}}{2^{sin x} + 2^{cos x}} d x

π / 2 \int 0 cos x d x

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