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Question

If dxx+x7=p(x) then , x6x+x7dx is eqaul to:

A
In|x|p (x)+c
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B
In|x|+p (x)+c
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C
xp (x)+c
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D
x+p (x)+c
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Solution

The correct option is A In|x|p (x)+c
dxx+x7=p(x)(Given)

Now,
x6x+x7dx=x6+11x+x7dx=x6+1x+x7dxdxx+x7=x6+1x(1+x6)dxdxx+x7dx=ln|x|p(x)+c

Hence, this is the answer.

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