If ∫8x43+13.x38(x13+x5+1)4dx=13.xa(xb+xc+1)3+C where a,b,cϵN,(a>b>c and where C is a constant of integration), then
A
a+b=39
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B
a+b=52
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C
a+b+c=57
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D
b−c=8
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Solution
The correct options are Ba+b=52 Ca+b+c=57 Db−c=8 I=∫8x9+13x14(1+1x8+1x13)4dxPut,1+1x8+1x13=t⇒(−8x9−13x14)dx=dt⇒I=∫−dtt4=13t3+C=13x39(x13+x5+1)3+Ca=39,b=13,c=5