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Question

If 8x43+13.x38(x13+x5+1)4dx=13.xa(xb+xc+1)3+C where a,b,c ϵ N,(a>b>c and where C is a constant of integration), then

A
a+b=39
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B
a+b=52
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C
a+b+c=57
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D
bc=8
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Solution

The correct options are
B a+b=52
C a+b+c=57
D bc=8
I=8x9+13x14(1+1x8+1x13)4dxPut,1+1x8+1x13=t(8x913x14)dx=dtI=dtt4=13t3+C=13x39(x13+x5+1)3+Ca=39,b=13,c=5

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