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Question

If (x)5(x)7+x6dx=a ln(xkxk+1)+c, the values of a and k respectively are

A
52 and 25
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B
25 and 52
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C
52 and 2
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D
None of these
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Solution

The correct option is B 25 and 52
I=dx(x)+(x)7=dx(x)7[1+1(x)5]
Put 1(x)5=ydydx=52(x)7)I=2 dy5(1+y)=25ln|1+y|+c=25ln[(x)5(x)5+1]+Ca=25,k=52

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