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Question

If (x1x+1)dxx3+x2+x=2tan1f(x)+C, find f(x).

A
x+1x+1
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B
x+1x+2
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C
x1x+1
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D
x1x1
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Solution

The correct option is A x+1x+1
I=(x1)dx(x+1)xx+1+1x=(x1)(x+1)dx(x+1)2xx+1+1x=(11x2)dx(x+1x+2)x+1x+1Put x+1+1x=t2(11x2)dx=2t dt=2t dt(t2+1)t=2tan1t+c=2tan1(x+1x+1)+c
f(x) = x+1x+1

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