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Question

If sinxdx =cosx+c1 , then 2sinxdx is equal to

A
cosx+c1
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B
2cosx+c1
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C
2cosx+c1
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D
cosx+c1
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Solution

The correct option is B 2cosx+c1
Given :- sinxdx=cosx+c1

Now as we can see that the required integration 2 times the given integration.

Hence we get:
2sinxdx=2cosx+c1

But as we know that c1 is a constant, so any other multiple of it will also be a constant, hence we get option B as the correct answer.

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