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Question

If x2e2x dx=e2x(ax2+bx+c)+d, where d is the constant of integration, then the value of abc is

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Solution

x2e2x dx=e2x(ax2+bx+c)+d,

Differentiating both the sides
x2e2x=e2x(2ax+b2(ax2+bx+c))x2=2ax2+(2a2b)x+b2c2a=1, 2a2b=0, b2c=0a=b=12, c=14abc=4

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