If integrating factor of x1-x2 d y-2 x2 y-y-a x3 d x-0 is e- P d x- then P is equal to

The correct option is C (2x^2 1)/x(1 x^2)x(1 x^2)dy+(2x^2y y ax^3)dx=0 dy/dx+(2x^2 1)/x(1 x^2)y=ax^2/(1 x^2), ∴ P=2x^2 1/x(1 x^2). ...

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Integrating Factor

If integratin...

Question

If integrating factor of $x (1 - x^{2}) d y + (2 x^{2} y - y - a x^{3}) d x = 0$ is $e^{\int P d x}$ , then P is equal to

\frac{2 x^{2} - a x^{3}}{x (1 - x^{2})}

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(2 x^{2} - 1)

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\frac{2 x^{2} - 1}{a x^{3}}

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\frac{(2 x^{2} - 1)}{x (1 - x^{2})}

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