Question

If internal radius of a hollow shaft is $\left(\frac{1}{4}\right)$ times the external radius, then ratio of torque carried by the hollow shaft and solid shaft of same cross-sectional area and subjected to the same maximum shear stress , will be

• A. 4.389
• B. 1.133
• C. 2.194
• D. 1.097

Answer 1

The correct option is D 1.097

$\left(\frac{T_{hollow}}{T_{solid}}\right)=\frac{1+n^2}{\sqrt{1-n^2}}=\frac{1+(\frac{1}{4}{)}^2}{\sqrt{1-(\frac{1}{4}{)}^2}}$

$=\frac{17}{4\sqrt{15}}=1.097$