If ionisation potential for hydrogen atom is 13.6 eV, then ionisation potential for $L i^{+ 2}$ will be:

119.4 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

120.4 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

122.4 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

54.4 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 122.4 eV
$E_{L i^{+ 2}} = E_{H} \times Z^{2}$
$= 13.6 \times 9$
= 122.4 eV

Suggest Corrections

Similar questions

13.6 e V

H e^{+}

L i^{2 +}

13.6 e V

13.6 e V

The ionisation energy of hydrogen atom is 13.6 ev. What will be the ionisation energy of ${L i}^{+ 2}$ ions?

Explore more