If ionization energy of $H -$ atoms is $x e V$ and $K E$ of electron in 3rd excited state of ${B e}^{+ 3}$ ion is $y$ $e V$ , Find ratio $\frac{y}{x}$ .

1

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2

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\frac{1}{3}

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\frac{1}{2}

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Solution

The correct option is A $1$
$K E = 13.6 \times \frac{Z^{2}}{n^{2}}$

$K E = 13.6 \times \frac{4^{2}}{4^{2}} = y$

$I E = 13.6 \times 1^{2} = x$

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