If ionization enthalpy of hydrogen atom is , the ionization enthalpy of $H e^{+}$ is:

-13.6 eV

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13.6 eV

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54.4 eV

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-54.4 eV

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Solution

The correct option is C 54.4 eV
$I o n i z a t i o n e n t h a l p y = 13.6 \times Z^{2} = 13.6 \times 4 = 54.4 e V$

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If ionization enthalpy of hydrogen atom is , the ionization enthalpy of He+ is:

The correct option is C 54.4 eVIonization enthalpy=13.6×Z2=13.6×4=54.4 eV

If ionization enthalpy of hydrogen atom is , the ionization enthalpy of $H e^{+}$ is:

The correct option is C 54.4 eV
$I o n i z a t i o n e n t h a l p y = 13.6 \times Z^{2} = 13.6 \times 4 = 54.4 e V$