If $$ is a binary operation on set $N$ ,of natural no defined as $a b = H C F$ of $(a, b)$ . Evaluate $3 * (2 * 5)$ .

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Solution

$a * b = H C F$ of $(a, b)$
$(2 * 5) = H C F$ of $(2, 5)$
$∴ (3 * 1) = H C F$ of $(3, 1)$
=3 Ans
$2 = 1 \times 2$
$5 = 1 \times 5$
$∴$ HCF of $2, 5 = 1$

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If ∗ is a binary operation on set N,of natural no defined as a∗b=HCF of (a,b). Evaluate 3∗(2∗5).

a∗b=HCF of (a,b)(2∗5)=HCF of (2,5)∴(3∗1)=HCF of (3,1)=3 Ans2=1×25=1×5∴ HCF of 2,5=1

If $$ is a binary operation on set $N$ ,of natural no defined as $a b = H C F$ of $(a, b)$ . Evaluate $3 * (2 * 5)$ .

$a * b = H C F$ of $(a, b)$
$(2 * 5) = H C F$ of $(2, 5)$
$∴ (3 * 1) = H C F$ of $(3, 1)$
=3 Ans
$2 = 1 \times 2$
$5 = 1 \times 5$
$∴$ HCF of $2, 5 = 1$