(i) −4 + 3 − (−2) = −4 + (3 + 2) = −4 + 5 = 1 (ii) −(−2) + (−3) − (−2) = (2 − 3) + 2 = −1 + 2 = 1 (iii) −6 + (−5) − (−2) = −6 + (−5 + 2) = −6 − 3 = −9 (iv) −(−5) + 6 − (−2) = 5 + (6 + 2) = 5 + 8 = 13
Question 126 (i)
If Δ is an operation, such that for integers a and b. We have aΔb=a×b−2×a×b+b×b (−a)×b+b×b, then find 4 Δ (−3) Also, show that 4 Δ (−3) ≠ (−3) Δ 4
Question 125 (ii)
If '*' is an operation have, such that for integers a and b. We have a∗b=a×b+(a×a+b×b), then find (−6)∗2