Question

If '$∆$' is an operation such that '$\mathrm{a}∆\mathrm{b}=\mathrm{a}+\mathrm{b}+\left(-2\right)$', then find $\left(-3\right)∆\left(-4\right)$

Answer 1

Step:Finding the value of $\left(-3\right)∆\left(-4\right)$.

Given: $\mathrm{a}∆\mathrm{b}=\mathrm{a}+\mathrm{b}+\left(-2\right)$

Here, $\mathrm{a}=-3$ and $\mathrm{b}=-4$

So, $\left(-3\right)∆\left(-4\right)=-3+\left(-4\right)+\left(-2\right)$

$=-3+\left[\left(-4\right)+\left(-2\right)\right]$ (Using the associative property of addition of integers)

$=-3+\left(-6\right)$ ($\because$ When both the integers are negative, the sum is also negative)

$=-9$

Therefore, the required answer is $-9$.