wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If is found, on heating a gas, its volume increase by 50% and pressure decreases to 60% of its original value. If the original temperature was15C, find the temperature to which is was heated?

Open in App
Solution

The gas has constant mass as it is ideal. So we can use the equation for the general transformation of the ideal gas:
The mixed gas formula: P1V1T1=P2V2T2

Given: T1 = -15°C+273 = 258 K

Assume: P1P_1P1 = P atm and P2P_2P2 = 60% decraesed, so it has, P2=60100×P

V1V_1V1 = V and V2V_2V2 incraesed by 50%, so it is, V2=1+50100×V=32×V
Plug in the values now,

T2 = P2V2P1V1

T2 =

P×V258=(35)P×(32)VT2

T2=258×3×P×3×V5×2×P×V

=232.2K


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Ideal Gas Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon