If it is 10.00 a.m. I.S.T., then what would be the local time at Shillong on 92° E longitude ?
The correct option is C 10.38 a.m.
Notes: IST meridian passes through 82.5 degree.
Difference between two given longitudes= 9.5 degrees.
As we know 1 degree= 4 minutes, therefore 9.5 degrees= 4 x 9.5= 38 minutes.
Thus, time is 10+38 minutes= 10:38 AM