If it is known that the third term of the binomial expansion $(x + x^{l o g_{10} x})^{5}$ is $10^{6}$ then $x$ is equal to

10

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10^{- 5 / 2}

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100

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5

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Solution

The correct options are
A $10$
B $10^{- 5 / 2}$

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Similar questions

{(x + x^{{log}_{10} x})}^{3} i s 10^{6}

x

{[x + x^{{log}_{10} x}]}^{5}

10^{6}

x

If the third term in the expansion of ${(\frac{1}{x} + x^{l o g} 10^{x})}^{5}$ is 1000, then x =

(\frac{1}{x} + x^{{log}_{10} x})^{5}

1, 000

x

{(\frac{1}{x} + x {log}_{10} x)}^{5}

1000

x

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