If it takes 8 minutes and 20 seconds for sunlight to reach the earth, find the distance between the Earth and the Sun. The velocity of light is $3 \times 10^{8} m s^{- 1}$ .

15 \times 10^{10} m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 \times 10^{10} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 \times 10^{10} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \times 10^{10} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $15 \times 10^{10} m$
Using the formula,
Distance $=$ speed $\times$ time.
Substituting speed of light $= 3 \times 10^{8} m s^{- 1}, t = 8 \times 60 + 20 = 500 s$ , we get
Distance $= 3 \times 10^{8} \times 500 = 15 \times 10^{10} m$ .

Suggest Corrections

Similar questions

The speed of light in air is :

(a) $3 \times 10^{8} m s^{- 1}$

(b) $330 m s^{- 1}$

(d) $3 \times 10^{10} m s^{- 1}$

Q. Light travels with a speed of 3 × 10⁸ m/s in vacuum. Sunlight takes 8.3 minutes to reach the earth. Calculate the distance between the earth and the sun.

It takes time 8 min for light to reach from the sun to the earth surface. If speed of light taken to be 3 $\times$ 10 $^{8}$ ms $^{- 1}$ , find the distance from the sun to the earth in km.

Q. The maximum electron density in the ionosphere in the morning is

10^{10} m^{- 3}

. At noon time, it increases to

2 \times 10^{10} m^{- 3}

. Find the ratio of critical frequency at noon and the critical frequency in the morning.

A signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station ? The signal travels at the speed of light, that is $3 \times 10^{8}$ m/s.

Join BYJU'S Learning Program

If it takes 8 minutes and 20 seconds for sunlight to reach the earth, find the distance between the Earth and the Sun. The velocity of light is 3×108ms−1.

The correct option is A 15×1010mUsing the formula,Distance = speed × time.Substituting speed of light =3×108ms−1,t=8×60+20=500s, we getDistance =3×108×500=15×1010m.

If it takes 8 minutes and 20 seconds for sunlight to reach the earth, find the distance between the Earth and the Sun. The velocity of light is $3 \times 10^{8} m s^{- 1}$ .

The correct option is A $15 \times 10^{10} m$
Using the formula,
Distance $=$ speed $\times$ time.
Substituting speed of light $= 3 \times 10^{8} m s^{- 1}, t = 8 \times 60 + 20 = 500 s$ , we get
Distance $= 3 \times 10^{8} \times 500 = 15 \times 10^{10} m$ .