Question

If it turns an angle of $yrad$ in these $3s$, then $2y$ is equal to $250+x$. Find $x$.

Answer 1

${\int }_{65}^{\omega }d\omega ={\int }_0^t(-10-5t)dt$
$\therefore \omega =65-[10t+2.5t^2]$
${\int }_0^{\theta }d\theta ={\int }_0^3\omega dt={\int }_0^3(65-10t-2.5t^2)dt$
$\therefore \theta =195-45-22.5=127.5rad$