If K>0 and the product of the roots of the equation x^2 - 3kx + 2e^2logk - 1 = 0 is 7 then the sum of the roots is
(A) 1. (B) 4. (C) 6. (D) 8.

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Solution

Product of the roots =
2e2 log k – 1

⇒7= 2e2 log k – 1

⇒2e2 log k – 1 = 7

⇒2e2 log k – 1 = 8

⇒e2 log k = 4

⇒2log k = log 22

⇒2log k = 2log 2

⇒k = 2
So the sum of roots =3k=3×2=6

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