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Heat Capacity at Constant Volume

If K =1.19 × ...

Question

If K=1.19×10-4 at 623K. Find 🔼G

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Solution

ΔG = - RT lnK (remember this equation) = - 8.314 * 623 * ln (1.9 * 10^-4) = -32455.007 J = -322.455007 KJ.

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F e^{2 +} + 3 d i p y r i d y l \Leftrightarrow [F e (d i p y r i d y l)_{3}]^{2 +} r_{f} = 1.45 \times 10^{13} [F e^{2 +}] [d i p y r i d y l]^{3} r_{b} = 1.22 \times 10^{- 4} [F e (d i p y r i d y l)]^{2 +}

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57 meV

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