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Heat Capacity at Constant Volume

If K =1.19 × ...

Question

If K=1.19×10-4 at 623K. Find 🔼G

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Solution

ΔG = - RT lnK (remember this equation) = - 8.314 * 623 * ln (1.9 * 10^-4) = -32455.007 J = -322.455007 KJ.

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Heat Capacity at Constant Volume

Standard XII Chemistry