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Characteristics of Equilibrium Constant

If K1 and ...

Question

If $K_{1}$ and $K_{2}$ are equilibrium constants for reactions (I) and (II) respectively for,
$N_{2} + O_{2} ⇌ 2 N O$ ............(I)
$\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇌ N O$ ..... (II)
then,

K_{2} = K_{1}

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K_{2} = \sqrt{K_{1}}

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K_{1} = 2 K_{2}

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K_{1} = \frac{1}{2} K_{2}

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Solution

The correct option is B $K_{2} = \sqrt{K_{1}}$
the reaction of I is X

and the reaction of II is X/2
so the $K_{2}$ is $(K_{1})^{1 / 2}$
Hence B is correct answer

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Similar questions

N_{2} + O_{2} ⇌ 2 N O, K_{1}

(\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2} ⇌ N O, K_{2}

2 N O ⇌ N_{2} + O_{2}; K_{3}

N O ⇌ (\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2}; K_{4}

K_{1}, K_{2}, K_{3}

K_{4}

N_{2} + O_{2} ⇋ 2 N O, K_{1}

\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇋ N O, K_{2}

2 N O ⇌ N_{2} + O_{2}; K_{3}

N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1} \times K_{3} = x; \sqrt{(K_{1})} \times K_{4} = y; \sqrt{(K_{3})} \times K_{2} = z

x y z

N_{2}

O_{2} ⇋ 2 N O

N O ⇋ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}

K_{1}

K_{2}

K

K_{1}

K_{2}

N_{2} + 2 O_{2} ⇋ 2 N O_{2}, K

N_{2} + O_{2} ⇋ 2 N O, K_{1}

2 N O + O_{2} ⇋ 2 N O_{2}, K_{2}

N_{2} + O_{2} ⇋ 2 N O, K_{1}; \frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇋ N O, K_{2};

2 N O ⇌ N_{2} + O_{2}, K_{3}; N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1}, K_{2}, K_{3}

K_{4}

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