You visited us 166 times! Enjoying our articles? Unlock Full Access!

Equilibrium Constant and Standard Free Energy Change

If K1 and ...

Question

If $K_{1}$ and $K_{2}$ are the equilibrium constants of the equilibriums $(A)$ and $(B)$ respectively, then what is the relationship between the two constants?
$(A)$ $S O_{2} (g) + 1 / 2 O_{2} (g) ⇋ S O_{3} (g), K_{1}$
$(B)$ $2 S O_{3} (g) ⇋ 2 S O_{2} (g) + O_{2} (g), K_{2}$

K_{1} = K_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{1} = \frac{1}{K_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{2} = K_{1}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_{1}^{2} = \frac{1}{K_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $K_{1}^{2} = \frac{1}{K_{2}}$
When the equilibrium reaction $(A)$ $S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇋ S O_{3} (g), K_{1}$ is reversed, a new equilibrium $(C)$ $S O_{3} (g) ⇋ S O_{2} (g) + \frac{1}{2} O_{2} (g), K_{3}$ is obtained.
The relationship between $K_{1}$ and $K_{3}$ is $K_{1} = \frac{1}{K_{3}}$ .
When equilibrium $(C)$ $S O_{3} (g) ⇋ S O_{2} (g) + \frac{1}{2} O_{2} (g), K_{3}$ is multiplied by $2$ , equilibrium ( $B$ ) $2 S O_{3} (g) ⇋ 2 S O_{2} (g) + O_{2} (g), K_{2}$ is obtained.
The relationship between $K_{2}$ and $K_{3}$ is $\frac{1}{K_{2}} = {(\frac{1}{K_{3}})}^{2}$ .
Thus, $\frac{1}{K_{2}} = {(\frac{1}{K_{3}})}^{2} = {K_{1}}^{2}$ .

Suggest Corrections

Similar questions

Q. The equilibrium constants of the reactions,

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

and

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

are

K_{1}

and

K_{2}

respectively. The relationship between

K_{1}

and

K_{2}

is:

Q. Two gaseous equilibria

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

and

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

have equilibrium constants

K_{1}

and

K_{2}

respectively at

298 K

. Which of the following relationships between

K_{1}

and

K_{2}

is correct:

Q. The equilibrium constants of the reactions

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇋ S O_{3} (g)

and

2 S O_{2} (g) + O_{2} (g) ⇋ 2 S O_{3} (g)

are

K_{1}

and

K_{2}

respectively.

The relationship between

K_{1}

and

K_{2}

will be :

Two gaseous equilibria $S O_{2} (g) + 0.5 O_{2} (g) ⇌ S O_{3} (g)$ and

$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ have equilibrium constants $K_{1}$ and $K_{2}$ respectively

at 298K. Which of the following relationships between $K_{1}$ and $K_{2}$ is correct

Q. Consider the equilibria (1) and (2) with equilibrium constants

K_{1}

and

K_{2}

respectively.

S O_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ S O_{3} (g)

...... (1)

2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

...... (2)

K_{1}

and

K_{2}

are related as:

Join BYJU'S Learning Program

If K1 and K2 are the equilibrium constants of the equilibriums (A) and (B) respectively, then what is the relationship between the two constants?(A) SO2(g)+1/2O2(g)⇋SO3(g), K1(B) 2SO3(g)⇋2SO2(g)+O2(g), K2

If $K_{1}$ and $K_{2}$ are the equilibrium constants of the equilibriums $(A)$ and $(B)$ respectively, then what is the relationship between the two constants?
$(A)$ $S O_{2} (g) + 1 / 2 O_{2} (g) ⇋ S O_{3} (g), K_{1}$
$(B)$ $2 S O_{3} (g) ⇋ 2 S O_{2} (g) + O_{2} (g), K_{2}$