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Question

If K1and K2 are the respective equilibrium constants for the two reactions
XeF6(g)+H2O(g)XeOF4(g)+2HF(g)

XeO4(g)+XeF6(g)XeOF4(g)+XeO3F2(g)
the equilibrium constant of the following reaction is:

XeO4(g)+2HF(g)XeO3F2(g)+H2O(g) will be:

A
K1/K22
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B
K1×K2
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C
K1/K2
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D
K2/K1
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Solution

The correct option is D K2/K1
For the reaction
XeF6(g)+H2O(g)XeOF4(g)+2HF(g)
K1=[XeOF4][HF]2[XeF6][H2O] . . . . . (1)
and for the reaction
XeO4(g)+XeF6(g)XeOF4(g)+XeO3F2(g)

K2=[XeOF4][XeO3F2][XeO4][XeF6] . . . . . (2)
For reaction :
XeO4(g)+2HF(g)XeO3F2(g)+H2O(g)

K=[XeO3F2][H2O][XeO4][HF]2...
Clearly, from (I) and (2) K=K2/K1

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