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Standard XII

Chemistry

Characteristics of Equilibrium Constant

If K 1, K 2 a...

Question

If $K_{1}, K_{2} a n d K_{3}$ are equilibrium constant for formation of $A D, A D_{2} a n d A D_{3}$ respectively as follow $A + D ⇌ A D, A D + D ⇌ A D_{2}, A D_{2} + D ⇌ A D_{3}$ then equilibrium constant 'K" for $A + 3 D ⇌ A D_{3}$ is related as

K_{1} + K_{2} + K_{3} = K

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log K_{1} + log K_{2} + log K_{3} = log K

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K_{1} + K_{2} = K_{3} + K

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log K_{1} + log K_{2} = log K_{3} + log K

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Solution

The correct option is B $log K_{1} + log K_{2} + log K_{3} = log K$
$A + D ⇌ A D; K_{1} A D + D ⇌ A D_{2}; K_{2} A D_{2} + D ⇌ A D_{3}; K_{3} A + 3 D ⇌ A D_{3}; K$
As we have that $K = K_{1} . K_{2} . K_{3}$
Taking log on both sides,
$log K = log K_{1} + log K_{2} + {log}_{3}$

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Similar questions

Q. If

K_{1}, K_{2} a n d K_{3}

are equilibrium constant for formation of

A D, A D_{2} a n d A D_{3}

respectively as follow

A + D ⇌ A D, A D + D ⇌ A D_{2}, A D_{2} + D ⇌ A D_{3}

then equilibrium constant 'K" for

A + 3 D ⇌ A D_{3}

is related as

Q. If

K_{1}, K_{2}, K_{3}

are equilibrium constant for formation of

A D_{1}, A D_{2}, A D_{3}

, respectively as follows

A + D ⇌ A D_{1}

A D_{1} + D ⇌ A D_{2}, A D_{2} + D ⇌ A D_{3}

. Then equilibrium constant 'K' for

A + 3 D ⇌ A D_{3}

is related as:

Q. For the reactions,

A ⇌ B, B ⇌ C, C ⇌ D

, equilibrium constants are

K_{1}, K_{2}, K_{3}

respectively.

What is the value of the equilibrium constant for

A ⇌ D

Q. For a reaction,

N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}

Given:

\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

The relation between

k_{1}, k_{2}

and

k_{3}

are:

For $C u^{2 +}$ ion in $[C u (H_{2} O)_{4} (e n)]^{2 +}, [C u (H_{2} O)_{2} (e n)_{2}]^{2 +}$ and $[C u (e n)_{3}]^{2 +}$ with the stability constant $k_{1}, k_{2}$ and $k_{3}$ respectively, which of the following holds true?

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Characteristics of Equilibrium Constant

Standard XII Chemistry

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If K1,K2 and K3 are equilibrium constant for formation of AD,AD2 and AD3 respectively as follow A+D⇌AD,AD+D⇌AD2,AD2+D⇌AD3 then equilibrium constant 'K" for A+3D⇌AD3 is related as

The correct option is B logK1+logK2+logK3=logKA+D⇌AD;K1AD+D⇌AD2;K2AD2+D⇌AD3;K3A+3D⇌AD3;K As we have that K=K1.K2.K3 Taking log on both sides, logK=logK1+logK2+log3

If $K_{1}, K_{2} a n d K_{3}$ are equilibrium constant for formation of $A D, A D_{2} a n d A D_{3}$ respectively as follow $A + D ⇌ A D, A D + D ⇌ A D_{2}, A D_{2} + D ⇌ A D_{3}$ then equilibrium constant 'K" for $A + 3 D ⇌ A D_{3}$ is related as

The correct option is B $log K_{1} + log K_{2} + log K_{3} = log K$
$A + D ⇌ A D; K_{1} A D + D ⇌ A D_{2}; K_{2} A D_{2} + D ⇌ A D_{3}; K_{3} A + 3 D ⇌ A D_{3}; K$
As we have that $K = K_{1} . K_{2} . K_{3}$
Taking log on both sides,
$log K = log K_{1} + log K_{2} + {log}_{3}$