If k + 2, k, 3k - 2 are three consecutive terms of A.P., then k = .................

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Solution

The correct option is B 0
Given : $k + 2, k, 3 k - 2$ are in A.P.
$∴ k - (k + 2) = (3 k - 2) - k$
$∴ k - k - 2 = 3 k - 2 - k$
$∴ - 2 = 2 k - 2$
$∴ 2 k = 0$
$∴ k = 0$
Hence, the answer is $0$ .

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