If k,2k−1 and 2k+1 are three consecutive terms of an A.P., the value of k is
A
2
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B
3
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C
−3
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D
5
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Solution
The correct option is B3 The three consecutive terms k,2k−1 and 2k+1 are an A.P., then We know that, second term - first term = third term - second term 2k−1−k=2k+1−2k+1 k−1=2 k=3.