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Question

If (k3),(2k+1) and (4k+3) are three consecutive terms of an A.P., find the value of k.

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Solution

Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.
(k3)+(4k+3)=2(2k+1)
5k=4k+2
k=2
Thus, the required value of k is 2.

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