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Question
If Ka of HCN=4×10−10, then the pH of 2.5×10−1molar HCN(aq) is:
If Ka of HCN=4×10−10, then the pH of 2.5×10−1molar HCN(aq) is:
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Solution
The correct option is D 5
[H3O+]=√Ka×C
=√4×10−10×2.5×101
=√10−10=10−5M
∵pH=−log[H3O+]
∴pH=−log(10−5)=5.
[H3O+]=√Ka×C
=√4×10−10×2.5×101
=√10−10=10−5M
∵pH=−log[H3O+]
∴pH=−log(10−5)=5.
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