Question

If $k$ belongs to set of natural numbers and $l=1,$ the particle starts at $(-1,0)$ the particle cross $x-$axis again at

• A. $(3,0)$
• B. $(1,0)$
• C. $(4,0)$
• D. $(2,0)$

Answer 1

The correct option is C $(4,0)$

Particle moves $1$ radian on each circle starts from $(-1,0)$.
To cross $x-$axis again should cover $\pi$ radian.
$\therefore \left(\frac{\pi }{1}\right)=\pi =3.14$
i.e., will be on $4^{th}$ circle.
$\Rightarrow$ point $(4,0)$