If $k = \frac{1}{2} m v^{2}$ solve for $v$ ' and find the value of $v$ , if $k = 100$ and $m = 2$ .

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Solution

The given quadratic equation is $k = \frac{1}{2} m v^{2}$ .

Substitute $k = 100$ and $m = 2$ in the equation $k = \frac{1}{2} m v^{2}$ as follows:

$k = \frac{1}{2} m v^{2} \Rightarrow 100 = \frac{1}{2} \times 2 v^{2} \Rightarrow v^{2} = 100 \Rightarrow v = \pm \sqrt{100} \Rightarrow v = \pm 10$

Hence, $v = \pm 10$ .

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If k=12mv2 solve for v' and find the value of v, if k=100 and m=2.

The given quadratic equation is k=12mv2.Substitute k=100 and m=2 in the equation k=12mv2 as follows: k=12mv2⇒100=12×2v2⇒v2=100⇒v=±√100⇒v=±10Hence, v=±10.

If $k = \frac{1}{2} m v^{2}$ solve for $v$ ' and find the value of $v$ , if $k = 100$ and $m = 2$ .