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Question

If k01x·f(3x)dx=03t·f(t)dt, then the value of k is:


A

9

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B

3

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C

19

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D

13

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Solution

The correct option is A

9


Explanation for the correct option:

Integration by substitution:

Let 3x=t, then dx=dt3.

k03t3·f(t)dt3=03t·f(t)dtk903t·f(t)dt=03t·f(t)dtk9=1k=9

Hence, option A is correct


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