Question

If $K_p$ is the equilibrium constant in terms of partial pressure and $K_{\chi }$ is the equilibrium constant in terms of mole fraction, then the relation between $K_p$ and $K_{\chi }$ for the following reaction is given by: $N_2{O}_4\left(g\right)\leftrightharpoons 2N{O}_2\left(g\right)$

• A. $K_p=K_{\chi }.P$
• B. $K_p=K_{\chi }.P^2$
• C. $K_p=K_{\chi }$
• D. $K_{\chi }=K_{p}P$

Answer 1

The correct option is A $K_p=K_{\chi }.P$

$N_2{O}_4\left(g\right)\leftrightharpoons 2N{O}_2\left(g\right)$
Here $\Delta n=2-1=1$
We know that
$K_p=K_{\chi }.P^{\Delta n}\Rightarrow K_p=K_{\chi }.P$