K - r - p - qr - k-p - qr - p - k-qlendvmatrix isA- 2 k 3B- 2 k 2C- k 3D- 3 k 2

The correct option is A 2k^3Δ = k+r amp;p amp;q r amp;k+p amp;q r amp;p amp;k+q C_1→ C_1+C_2+C_3, Δ = k+k amp;p amp;q k+k amp;k+p amp; ...

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Distance Formula

k + r & p & q...

Question

If $k = p + q + r$ , then the value of $∣ ∣ ∣ ∣ \begin{matrix} k + r & p & q r & k + p & q r & p & k + q \end{matrix} ∣ ∣ ∣ ∣$ is

2 k^{2}

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2 k^{3}

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k^{3}

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3 k^{2}

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Solution

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Similar questions

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 1 & 1 2 & 4 & 1 2 & 3 & 1 \end{matrix} ⎤ ⎥ ⎦, B = [\begin{matrix} 2 & 3 3 & 4 \end{matrix}]

P

B P A = [\begin{matrix} 1 & 0 & 1 0 & 1 & 0 \end{matrix}]

P =

[\begin{matrix} k & m & n p & - q & r \end{matrix}]

(k + m + n + p + q + r)

The relation between equilibrium constant $K_{P}$ and $K_{C}$ is

p^{2} + q r + p q + p r

k = p + q + r

∣ ∣ ∣ ∣ \begin{matrix} k + r & p & q r & k + p & q r & p & k + q \end{matrix} ∣ ∣ ∣ ∣

[p^{2} + (q r)^{2}] [p^{2} - (q r)^{2}]

p = 1, q = 2, r = 3

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