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Question

If k represents an integer, which of the following must be even integers?
2k,2k+6,8k4,3k+5,2k1

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Solution

  • 2k is always even
  • 2k+6 is always even
  • 8k/4=2k is always even
  • 3k+5 is even for odd k and odd for even k
  • 2k1 is always odd
  • So the correct answer is 2k,2k+6,8k/4

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