Question

If $K_{sp}$ for $AgCl=1.7\times {10}^{-10}$, then find the concentration of the ${Ag}^{+}$ ion in a saturated solution of $AgCl$?

• A. $1.7\times {10}^{-10}M$
• B. $3.4\times {10}^{-10}M$
• C. $1.3\times {10}^{-5}M$
• D. $2.6\times {10}^{-5}M$

Answer 1

Answer: (C)

$1.3\times {10}^{-5}M$

$K_{sp}=1.7\times {10}^{-10}$

$AgCl\leftrightharpoons A{g}^{+}+C{l}^{-}$

Let, the solubility for each ion is $S$.

Then , $K_{sp}=\left[A{g}^{+}\right]\left[C{l}^{-}\right]=S^2$

So, $S^2=1.7\times {10}^{-10}$

$\therefore S=1.3\times {10}^{-5}$